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Systems of Linear Inequalities

A free Algebra I lesson from the “Systems of Linear Equations and Inequalities” unit, with a worked example and practice problems including step-by-step solutions.

A system of linear inequalities is solved by graphing each inequality and finding the overlap of the shaded regions. A point is a solution only when it satisfies EVERY inequality in the system — substitute and check all of them. In Systems of Linear Equations and Inequalities, students need more than a memorized rule: they need to recognize the structure, select a method, carry out the algebra cleanly, and interpret the answer in a graph, table, equation, or real context. The expanded practice now mixes skill fluency, transfer questions, and cumulative review so the lesson builds durable Algebra I readiness.

What you'll learn

Why it matters: Production planning (machine time limit AND minimum output), nutrition planning (calorie ceiling AND protein floor), and budget allocation problems all use overlapping inequality regions.

Worked example

Problem. Is (3, 1) a solution of the system y > x - 2 AND y < 2x?

  1. Check first: is 1 > 3 - 2 = 1? No (strictly greater fails).
  2. Because one inequality fails, (3, 1) is NOT a solution of the system.
  3. Connect the result back to Systems of Linear Inequalities so the method and meaning are both clear.
  4. Check the result against the original representation before writing the final answer.

Answer: No

Lesson preview: this page shows 5 practice items. The interactive activity contains 28 practice items and 15 quiz items (multiple choice and typed response). Counts include repeated prompts and variants.

Practice problems

1. Is (2, 3) a solution of {y < 5 AND y > 0}?

Choices: Yes · No

Show solution
  1. Check: 3 < 5 yes; 3 > 0 yes.
  2. Both hold, so (2, 3) is a solution.

Answer: Yes

2. Is (3, 1) a solution of {y > x - 2 AND y < 2x}?

Choices: Yes · No

Show solution
  1. Check first: 1 > 3 - 2 = 1 fails.
  2. Strict > is not satisfied, so not a solution.

Answer: No

3. Is (1, 2) a solution of {y > x AND y < 2x + 1}?

Choices: Yes · No

Show solution
  1. Check: 2 > 1 yes; 2 < 3 yes.
  2. Both hold.

Answer: Yes

4. Is (0, 0) a solution of {y >= 0 AND x >= 0}?

Choices: Yes · No

Show solution
  1. Both 0 >= 0 statements hold.
  2. So (0, 0) is on the boundary of both and counts.

Answer: Yes

5. Is (-1, 2) a solution of {y > 0 AND x > 0}?

Choices: Yes · No

Show solution
  1. First: 2 > 0 yes. Second: -1 > 0 NO.
  2. Fails the x condition.

Answer: No

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