Complex Solutions of Quadratics
A free Algebra II lesson from the “Complex Numbers” unit, with a worked example and practice problems including step-by-step solutions.
When a quadratic's discriminant is negative, it has no real roots but two complex roots. Complex roots for real-coefficient quadratics come in conjugate pairs.
What you'll learn
- Recognize when quadratics have complex solutions
- Use square roots of negatives
- Write conjugate solution pairs
Worked example
Problem. Solve x^2 + 9 = 0.
- Subtract 9 to get x^2 = -9.
- Take square roots.
- x = +/- sqrt(-9) = +/- 3i.
Answer: x = 3i and x = -3i
Practice problems
1. Solve x^2 + 16 = 0.
Choices: x = 4i and x = -4i · x = 4 and x = -4 · x = 16i · No solutions
Show solution
- Warm-up: First identify exactly what the question is asking: Solve x^2 + 16 = 0.
- Use inverse operations to isolate the unknown, and keep both sides balanced at every step.
- x^2 = -16.
- Verify the selected choice by checking that it satisfies the original prompt and that the other choices fail the same test.
Answer: x = 4i and x = -4i
2. Find the discriminant of x^2 + 4x + 8 = 0.
Show solution
- Warm-up: First identify exactly what the question is asking: Find the discriminant of x^2 + 4x + 8 = 0.
- Use inverse operations to isolate the unknown, and keep both sides balanced at every step.
- b^2 - 4ac = 16 - 32.
- Check the result by substituting or estimating: the response should match -16 and make sense in the original problem.
Answer: -16
3. A discriminant of -20 means the solutions are...
Choices: Complex · Two real · One repeated real · Linear
Show solution
- Core Practice: First identify exactly what the question is asking: A discriminant of -20 means the solutions are...
- For signed numbers, track both distance from zero and direction so the sign of the answer makes sense.
- Negative discriminants give complex roots.
- Verify the selected choice by checking that it satisfies the original prompt and that the other choices fail the same test.
Answer: Complex
4. If 2 + 5i is a root of a real quadratic, the other root is...
Choices: 2 - 5i · -2 + 5i · -2 - 5i · 5 + 2i
Show solution
- Challenge: First identify exactly what the question is asking: If 2 + 5i is a root of a real quadratic, the other root is...
- For quadratics, track the zeros, vertex, or coefficients so the algebra matches the graph feature being asked about.
- Complex roots come in conjugate pairs.
- Verify the selected choice by checking that it satisfies the original prompt and that the other choices fail the same test.
Answer: 2 - 5i
5. Find the discriminant of x^2 - 6x + 13 = 0.
Show solution
- Mixed Review: First identify exactly what the question is asking: Find the discriminant of x^2 - 6x + 13 = 0.
- Use inverse operations to isolate the unknown, and keep both sides balanced at every step.
- Use b^2 - 4ac.
- (-6)^2 - 4(1)(13) = 36 - 52.
- The discriminant is -16, so the roots are complex.
- Check the result by substituting or estimating: the response should match -16 and make sense in the original problem.
Answer: -16
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