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Rational Expressions

A free Algebra II lesson from the “Equations, Rational Functions, and Conics” unit, with a worked example and practice problems including step-by-step solutions.

A rational expression is a fraction with polynomials. Factor numerator and denominator first, cancel only common factors, and keep excluded values from the original denominator.

What you'll learn

Why it matters: Mixing ratios, work-rate problems, and electrical-resistance sums combine rational expressions. Factoring before adding is what reveals the common denominator, and noting excluded values is what keeps the answer mathematically honest.

Worked example

Problem. Simplify (x^2 - 9)/(x - 3).

  1. Factor x^2 - 9 as (x - 3)(x + 3).
  2. Cancel the common factor x - 3.
  3. The original denominator means x cannot be 3.

Answer: x + 3, x != 3

Lesson preview: this page shows 5 practice items. The interactive activity contains 28 practice items and 15 quiz items (multiple choice and typed response). Counts include repeated prompts and variants.

Practice problems

1. Simplify (x^2 - 16)/(x - 4).

Choices: x + 4, x != 4 · x - 4 · x + 4, x != -4 · x^2 + 4

Show solution
  1. Factor difference of squares.

Answer: x + 4, x != 4

2. For 1/(x + 7), what value is excluded?

Show solution
  1. The denominator cannot be zero.

Answer: -7

3. Simplify (x^2 + 5x)/(x).

Choices: x + 5, x != 0 · x^2 + 5 · 5x · x + 5, x != -5

Show solution
  1. Factor x(x + 5), then cancel x.

Answer: x + 5, x != 0

4. Simplify (x^2 - x - 6)/(x - 3).

Choices: x + 2, x != 3 · x - 2 · x + 3 · x + 2, x != -2

Show solution
  1. Factor as (x - 3)(x + 2).

Answer: x + 2, x != 3

5. Which expression has excluded values 2 and -5?

Choices: 1/((x - 2)(x + 5)) · 1/((x + 2)(x - 5)) · (x - 2)/(x + 5) · (x + 5)/(x - 2)

Show solution
  1. Set each denominator factor equal to zero.

Answer: 1/((x - 2)(x + 5))

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