Parametric Equations
A free Precalculus lesson from the “Parametric, Polar, Vectors, and Intro to Limits” unit, with a worked example and practice problems including step-by-step solutions.
Parametric equations use a third variable, often time, to describe x and y together. This lesson is part of Precalculus: Advanced Functions, so the emphasis is on interpreting behavior, choosing the right representation, and explaining the result clearly rather than memorizing isolated algebra moves.
What you'll learn
- Evaluate and interpret x(t), y(t) pairs
- Use parametric equations in symbolic and graph-based problems
- Check common mistakes before finalizing an answer
Worked example
Problem. For x = t + 2 and y = t^2 - 2, find the point (x, y) when t = 2.
- Substitute t = 2 into x = t + 2: x = 2 + 2 = 4.
- Substitute t = 2 into y = t^2 - 2: y = 2^2 - 2 = 4 - 2 = 2.
- So the point is (4, 2).
Answer: (4, 2)
Practice problems
1. For x = t + 2 and y = t^2 - 2, find the point (x, y) when t = 2.
Show solution
- Substitute t = 2 into x = t + 2: x = 2 + 2 = 4.
- Substitute t = 2 into y = t^2 - 2: y = 2^2 - 2 = 4 - 2 = 2.
- So the point is (4, 2).
Answer: (4, 2)
2. For x = 4t + 3 and y = t^2 + 3, find the point (x, y) when t = 3.
Show solution
- Substitute t = 3 into x = 4t + 3: x = 4(3) + 3 = 12 + 3 = 15.
- Substitute t = 3 into y = t^2 + 3: y = 3^2 + 3 = 9 + 3 = 12.
- So the point is (15, 12).
Answer: (15, 12)
3. For x = 2t + 4 and y = t^2 + 4, find only the x-coordinate when t = 4.
Show solution
- Core Practice: First identify exactly what the question is asking: For x = 2t + 4 and y = t^2 + 4, find only the x-coordinate when t = 4.
- Use inverse operations to isolate the unknown, and keep both sides balanced at every step.
- Use the x-rule x = 2t + 4.
- Substitute t = 4: x = 2(4) + 4 = 8 + 4.
- So x = 12.
- Check the result by substituting or estimating: the response should match 12 and make sense in the original problem.
Answer: 12
4. For x = 3t + 1 and y = t^2 + 5, find only the y-coordinate when t = 1.
Show solution
- Core Practice: First identify exactly what the question is asking: For x = 3t + 1 and y = t^2 + 5, find only the y-coordinate when t = 1.
- Use inverse operations to isolate the unknown, and keep both sides balanced at every step.
- Use the y-rule y = t^2 + 5.
- Substitute t = 1: y = 1^2 + 5 = 1 + 5.
- So y = 6.
- Check the result by substituting or estimating: the response should match 6 and make sense in the original problem.
Answer: 6
5. A point moves with x = 4t + 2 and y = t^2 + 1. Where is it at the start, t = 0?
Show solution
- Core Practice: First identify exactly what the question is asking: A point moves with x = 4t + 2 and y = t^2 + 1. Where is it at the start, t = 0?
- Use inverse operations to isolate the unknown, and keep both sides balanced at every step.
- At t = 0, x = 4(0) + 2 = 2.
- At t = 0, y = 0^2 + 1 = 1.
- So the starting point is (2, 1).
- Check the result by substituting or estimating: the response should match (2, 1) and make sense in the original problem.
Answer: (2, 1)
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