Zeros and Multiplicity
A free Precalculus lesson from the “Polynomial Functions” unit, with a worked example and practice problems including step-by-step solutions.
Odd multiplicity usually crosses the x-axis; even multiplicity usually touches and turns. This lesson is part of Precalculus: Advanced Functions, so the emphasis is on interpreting behavior, choosing the right representation, and explaining the result clearly rather than memorizing isolated algebra moves.
What you'll learn
- Use zeros and multiplicity to predict crossing or touching behavior
- Use zeros and multiplicity in symbolic and graph-based problems
- Check common mistakes before finalizing an answer
Worked example
Problem. In p(x) = (x - 3)^2(x - 7)^3(x - 10)^4, what is the multiplicity of the zero x = 3?
- Multiplicity is the exponent on the matching factor.
- The factor (x - 3) is raised to the power 2.
- So the zero x = 3 has multiplicity 2.
Answer: 2
Practice problems
1. In p(x) = (x - 3)^2(x - 7)^3(x - 10)^4, what is the multiplicity of the zero x = 3?
Show solution
- Multiplicity is the exponent on the matching factor.
- The factor (x - 3) is raised to the power 2.
- So the zero x = 3 has multiplicity 2.
Answer: 2
2. In p(x) = (x - 4)^1(x - 8)^4(x - 11)^3, the factor (x - 8) is raised to what power?
Show solution
- The exponent on a factor is the multiplicity of its zero.
- Find (x - 8) and read its exponent: it is raised to the power 4.
- So the factor (x - 8) is raised to the power 4.
Answer: 4
3. For p(x) = (x - 5)^2(x - 6)^2(x - 12)^4, the degree equals the sum of all multiplicities. Find the degree.
Show solution
- Core Practice: First identify exactly what the question is asking: For p(x) = (x - 5)^2(x - 6)^2(x - 12)^4, the degree equals the sum of all multiplicities. Find the degree.
- For function notation, treat the value inside parentheses as the input and carefully substitute it into the rule.
- Add the exponents: 2 + 2 + 4.
- 2 + 2 + 4 = 8.
- The sum of multiplicities is the degree, so the degree is 8.
- Check the result by substituting or estimating: the response should match 8 and make sense in the original problem.
Answer: 8
4. How many DISTINCT zeros does p(x) = (x - 2)^1(x - 7)^3(x - 13)^3 have?
Show solution
- Count the different factors, not the exponents.
- The distinct factors are (x - 2), (x - 7), and (x - 13).
- So there are 3 distinct zeros.
Answer: 3
5. How many DISTINCT zeros does p(x) = (x - 3)^2(x - 8)^4 have?
Show solution
- Count the different factors, ignoring exponents.
- The distinct factors are (x - 3) and (x - 8).
- So there are 2 distinct zeros.
Answer: 2
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