Compound Inequalities
A free Algebra I lesson from the “Algebra Foundations” unit, with a worked example and practice problems including step-by-step solutions.
A compound inequality joins two inequalities with 'and' or 'or'. An 'and' (like 2 < x < 7) requires both conditions; the solution is the overlap. An 'or' (like x < -3 or x > 5) requires either; the solution is the union. Solve each piece the same way you solve a single inequality.
What you'll learn
- Solve 'and' compound inequalities (between two values)
- Solve 'or' compound inequalities (outside two values)
- Decide whether a given value satisfies a compound inequality
Worked example
Problem. Solve 1 < 2x + 3 <= 7.
- Subtract 3 from all three parts: -2 < 2x <= 4.
- Divide all three parts by 2: -1 < x <= 2.
Answer: -1 < x <= 2
Practice problems
1. In 2 < x < 7, what is the left boundary?
Show solution
- Warm-up: First identify exactly what the question is asking: In 2 < x < 7, what is the left boundary?
- Choose the operation or relationship that matches the wording, then carry it out one clear step at a time.
- The left boundary is the lower bound.
- x is greater than 2.
- Check the result by substituting or estimating: the response should match 2 and make sense in the original problem.
Answer: 2
2. For x < -3 or x > 5, give the smallest positive boundary on the right side.
Show solution
- Warm-up: First identify exactly what the question is asking: For x < -3 or x > 5, give the smallest positive boundary on the right side.
- For signed numbers, track both distance from zero and direction so the sign of the answer makes sense.
- The right-hand piece is x > 5.
- Its boundary is 5.
- Check the result by substituting or estimating: the response should match 5 and make sense in the original problem.
Answer: 5
3. Solve 4 <= x + 2 <= 9. Enter the lower bound of x.
Show solution
- Warm-up: First identify exactly what the question is asking: Solve 4 <= x + 2 <= 9. Enter the lower bound of x.
- Use inverse operations to isolate the unknown, and keep both sides balanced at every step.
- Subtract 2 from all parts: 2 <= x <= 7.
- Lower bound is 2.
- Check the result by substituting or estimating: the response should match 2 and make sense in the original problem.
Answer: 2
4. Solve 3x > 6 and 2x < 14 (the 'and' overlap). Enter the upper bound of x.
Show solution
- Core Practice: First identify exactly what the question is asking: Solve 3x > 6 and 2x < 14 (the 'and' overlap). Enter the upper bound of x.
- Use inverse operations to isolate the unknown, and keep both sides balanced at every step.
- First: x > 2. Second: x < 7.
- Overlap is 2 < x < 7. Upper bound is 7.
- Check the result by substituting or estimating: the response should match 7 and make sense in the original problem.
Answer: 7
5. Solve -2 < 3x + 1 < 10. Enter the upper bound of x.
Show solution
- Core Practice: First identify exactly what the question is asking: Solve -2 < 3x + 1 < 10. Enter the upper bound of x.
- For signed numbers, track both distance from zero and direction so the sign of the answer makes sense.
- Subtract 1: -3 < 3x < 9.
- Divide by 3: -1 < x < 3. Upper bound is 3.
- Check the result by substituting or estimating: the response should match 3 and make sense in the original problem.
Answer: 3
Practice this interactively with instant feedback and an AI tutor.
Practice Compound Inequalities Take the free placement check