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Exponential Growth and Decay

A free Algebra I lesson from the “Exponential Functions and Sequences” unit, with a worked example and practice problems including step-by-step solutions.

For exponential growth at rate r per period: y = a * (1 + r)^t. For decay (loss) at rate r per period: y = a * (1 - r)^t. Here a is the starting amount and t is the number of periods. Compound interest, population growth, and depreciation all fit one of these forms. Doubling means multiplying by 2; doubling time is the time needed for that change. If a population doubles every 6 hours, its doubling time is 6 hours and its multiplier over each 6-hour interval is 2.

What you'll learn

Why it matters: Bank accounts (compound interest), car values (depreciation), medicine doses (half-life), and bacteria cultures all use this model.

Worked example

Problem. $1000 invested at 5% annual compound interest. Value after 3 years?

  1. y = 1000 * (1.05)^3.
  2. (1.05)^3 = 1.157625.
  3. y = 1000 * 1.157625 = 1157.625.
  4. Connect the result back to Exponential Growth and Decay so the method and meaning are both clear.

Answer: 1157.625

Lesson preview: this page shows 5 practice items. The interactive activity contains 28 practice items and 15 quiz items (typed response and multiple choice). Counts include repeated prompts and variants.

Practice problems

1. $500 at 4% annual compound interest. Value after 2 years? (Round to 2 decimal places.)

Show solution
  1. y = 500 * (1.04)^2 = 500 * 1.0816 = 540.80.

Answer: 540.80

2. A car worth $20,000 depreciates 10% per year. Value after 1 year?

Show solution
  1. y = 20000 * (1 - 0.10) = 20000 * 0.90 = 18000.

Answer: 18000

3. 200 bacteria double every hour. Count after 3 hours?

Show solution
  1. y = 200 * 2^3 = 200 * 8 = 1600.

Answer: 1600

4. An 80-gram radioactive sample halves every year. Amount after 3 years?

Show solution
  1. y = 80 * (1/2)^3 = 80 * 1/8 = 10.

Answer: 10

5. $1000 at 8% annual compound. Value after 2 years? (Round to 2 decimal places.)

Show solution
  1. y = 1000 * (1.08)^2 = 1000 * 1.1664 = 1166.40.

Answer: 1166.40

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