Finding Inverses Algebraically
A free Precalculus lesson from the “Inverse Functions” unit, with a worked example and practice problems including step-by-step solutions.
To find an inverse, write y = f(x), swap x and y, then solve for y. This lesson is part of Precalculus: Advanced Functions, so the emphasis is on interpreting behavior, choosing the right representation, and explaining the result clearly rather than memorizing isolated algebra moves.
What you'll learn
- Find inverse rules by swapping x and y and solving
- Use finding inverses algebraically in symbolic and graph-based problems
- Check common mistakes before finalizing an answer
Worked example
Problem. Find the inverse of f(x) = 3x + 2. Enter in terms of x.
- Worked Example: First identify exactly what the question is asking: Find the inverse of f(x) = 3x + 2. Enter in terms of x.
- For function notation, treat the value inside parentheses as the input and carefully substitute it into the rule.
- Write y = 3x + 2.
- Swap x and y: x = 3y + 2.
- Solve for y: y = (x - 2)/3.
- Check the result by substituting or estimating: the response should match (x - 2)/3 and make sense in the original problem.
Answer: (x - 2)/3
Practice problems
1. Find the inverse of f(x) = 3x + 2. Enter in terms of x.
Show solution
- Warm-up: First identify exactly what the question is asking: Find the inverse of f(x) = 3x + 2. Enter in terms of x.
- For function notation, treat the value inside parentheses as the input and carefully substitute it into the rule.
- Write y = 3x + 2.
- Swap x and y: x = 3y + 2.
- Solve for y: y = (x - 2)/3.
- Check the result by substituting or estimating: the response should match (x - 2)/3 and make sense in the original problem.
Answer: (x - 2)/3
2. Find the inverse of f(x) = 4x + 3. Enter in terms of x.
Show solution
- Warm-up: First identify exactly what the question is asking: Find the inverse of f(x) = 4x + 3. Enter in terms of x.
- For function notation, treat the value inside parentheses as the input and carefully substitute it into the rule.
- Write y = 4x + 3.
- Swap x and y: x = 4y + 3.
- Solve for y: y = (x - 3)/4.
- Check the result by substituting or estimating: the response should match (x - 3)/4 and make sense in the original problem.
Answer: (x - 3)/4
3. Find the inverse of f(x) = 5x + 4. Enter in terms of x.
Show solution
- Core Practice: First identify exactly what the question is asking: Find the inverse of f(x) = 5x + 4. Enter in terms of x.
- For function notation, treat the value inside parentheses as the input and carefully substitute it into the rule.
- Write y = 5x + 4.
- Swap x and y: x = 5y + 4.
- Solve for y: y = (x - 4)/5.
- Check the result by substituting or estimating: the response should match (x - 4)/5 and make sense in the original problem.
Answer: (x - 4)/5
4. Find the inverse of f(x) = (x - 5)/2. Enter in terms of x.
Show solution
- Core Practice: First identify exactly what the question is asking: Find the inverse of f(x) = (x - 5)/2. Enter in terms of x.
- For function notation, treat the value inside parentheses as the input and carefully substitute it into the rule.
- Write y = (x - 5)/2.
- Multiply by 2: 2y = x - 5.
- Swap and solve to get f inverse(x) = 2x + 5.
- Check the result by substituting or estimating: the response should match 2x + 5 and make sense in the original problem.
Answer: 2x + 5
5. Find the inverse of f(x) = (x - 1)/3. Enter in terms of x.
Show solution
- Core Practice: First identify exactly what the question is asking: Find the inverse of f(x) = (x - 1)/3. Enter in terms of x.
- For function notation, treat the value inside parentheses as the input and carefully substitute it into the rule.
- Write y = (x - 1)/3.
- Multiply by 3: 3y = x - 1.
- Swap and solve to get f inverse(x) = 3x + 1.
- Check the result by substituting or estimating: the response should match 3x + 1 and make sense in the original problem.
Answer: 3x + 1
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