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Domain Restrictions and Holes

A free Precalculus lesson from the “Rational Functions” unit, with a worked example and practice problems including step-by-step solutions.

A canceled factor creates a hole; an uncanceled denominator factor creates a vertical asymptote. This lesson is part of Precalculus: Advanced Functions, so the emphasis is on interpreting behavior, choosing the right representation, and explaining the result clearly rather than memorizing isolated algebra moves.

What you'll learn

Why it matters: Rational functions model rates, constraints, efficiency, and quantities that change sharply near restricted inputs.

Worked example

Problem. In r(x) = (x - 2)/((x - 2)(x + 4)), what occurs at x = 2?

  1. The factor x minus the same value cancels.
  2. Canceled restrictions become holes.
  3. Uncanceled denominator factors become vertical asymptotes.

Answer: a hole

Practice problems

1. In r(x) = (x - 2)/((x - 2)(x + 4)), what occurs at x = 2?

Choices: a hole · a vertical asymptote · a horizontal asymptote · no restriction

Show solution
  1. The factor x minus the same value cancels.
  2. Canceled restrictions become holes.
  3. Uncanceled denominator factors become vertical asymptotes.

Answer: a hole

2. In r(x) = (x - 3)/((x - 3)(x + 5)), what occurs at x = 3?

Choices: a hole · a vertical asymptote · a horizontal asymptote · no restriction

Show solution
  1. The factor x minus the same value cancels.
  2. Canceled restrictions become holes.
  3. Uncanceled denominator factors become vertical asymptotes.

Answer: a hole

3. In r(x) = (x - 4)/((x - 4)(x + 6)), what occurs at x = 4?

Choices: a hole · a vertical asymptote · a horizontal asymptote · no restriction

Show solution
  1. The factor x minus the same value cancels.
  2. Canceled restrictions become holes.
  3. Uncanceled denominator factors become vertical asymptotes.

Answer: a hole

4. After simplifying (x - 1)/((x - 1)(x + 3)), what x-value marks the hole?

Show solution
  1. Core Practice: First identify exactly what the question is asking: After simplifying (x - 1)/((x - 1)(x + 3)), what x-value marks the hole?
  2. Choose the operation or relationship that matches the wording, then carry it out one clear step at a time.
  3. The factor x - 1 cancels.
  4. The original denominator was zero at x = 1.
  5. That canceled restriction is a hole at x = 1.
  6. Check the result by substituting or estimating: the response should match 1 and make sense in the original problem.

Answer: 1

5. After simplifying (x - 2)/((x - 2)(x + 4)), what x-value marks the hole?

Show solution
  1. Core Practice: First identify exactly what the question is asking: After simplifying (x - 2)/((x - 2)(x + 4)), what x-value marks the hole?
  2. Choose the operation or relationship that matches the wording, then carry it out one clear step at a time.
  3. The factor x - 2 cancels.
  4. The original denominator was zero at x = 2.
  5. That canceled restriction is a hole at x = 2.
  6. Check the result by substituting or estimating: the response should match 2 and make sense in the original problem.

Answer: 2

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